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Proof step 25 from proof to-to-leq (previous step)

m < # x, m ≤ n0, m ≤ n0 + 1, n0 < # x, ∀ m, x. m ≤ n0 ∧ n0 ≤ # x ∧ m ≤ # x → x to n0 to m = x to m ⊦ x = [], x to n0 to m = x to m

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: m, x

Additional information

Used simplifier rules: lels-03: ⊦ m < n → m ≤ n; from specification nat Used terms: m, x