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Proof step 1 from proof to-to-ls (conclusion)

¬ # σ < ⌜n⌝ ⊦ m < n → σ to n to m = σ to m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
m < n ⊦ σ to n to m = σ to m, n = 0, # σ < ⌜n⌝

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1