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Proof step 1 from proof to-unwind-end-fin (conclusion)

m < # x ⊦ x to m + 1 = (x to m) + x[m] '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
m < # x ⊦ x to m + 1 = (x to m) + x[m] ', x = []

Rule argument

Additional information

Used simplifier rules: l: ⊦ # x = 0 ↔ x = []; from specification list-data%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1