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Proof step 11 from proof to-unwind-end (previous step)

m < # x ⊦ (x to m) + x[m] ' = x to m + 1, ⌜a '⌝ + ⌜x⌝ = [], x = []

User applied rule insert lemma

And obtained the following new goals

Proof step 12:
m < # x ⊦ x to m + 1 = (x to m) + x[m] '

Rule argument

spec: inst: name: to-unwind-end-fin seq: m < # x ⊦ x to m + 1 = (x to m) + x[m] ' subst: [m, x] → [m, x] flags: current, []

Additional information

Used terms: m, x