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Proof step 16 from proof to-unwind-end (previous step)

⊦ ⌜λ n. (n = 0 ⊃ a;nf(n -1))⌝ = [], (nf to m) + nf(m) ' = nf to m + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
⊦ (nf to m) + nf(m) ' = nf to m + 1

Rule argument

Additional information

Used simplifier rules: fun-nonempty: ⊦ [] ≠ ⌜nf⌝ ;%pred-03: ⊦ n -1 = n - 1; from specification nat