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Proof step 18 from proof to-unwind-end (previous step)

∀ nf. (nf to m0) + nf(m0) ' = nf to m0 + 1 ⊦ (nf to m0 +1) + nf(m0 +1) ' = nf to m0 +1 + 1

User applied rule all left

And obtained the following new goals

Proof step 19:
((λ n. nf(n + 1)) to m0) + nf(m0 + 1) ' = (λ n. nf(n + 1)) to m0 + 1 ⊦ (nf to m0 +1) + nf(m0 +1) ' = nf to m0 +1 + 1

Rule argument

pos: left 1 terms: λ n. nf(n + 1) abort: F discard: T computed: F

Additional information

Used terms: λ n. nf(n + 1)