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Proof step 22 from proof to-unwind-end (previous step)

((λ n. nf(n + 1)) to m0) + nf(m0 + 1) ' = (λ n. nf(n + 1)) to m0 + 1, nf(m0 + 1) ∈ (λ n. nf(n + 1)) to m0 + 1 ⊦ (nf to m0 + 1) + nf(m0 + 1) ' = nf(0) ' + ((λ n. nf(n + 1)) to m0 + 1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 23:
⊦ nf to n + 1 = nf(0) + ((λ n. nf(n + 1)) to n)

Rule argument

spec: stream inst: name: to-succ-nf seq: ⊦ nf to n + 1 = nf(0) + ((λ n. nf(n + 1)) to n) subst: [n, nf] → [m0, nf] flags: rewrite, current

Additional information

Used simplifier rules: c: ⊦ a + x = a ' + x; from specification list%a: ⊦ (x + y) + z = x + y + z; from specification list%app-08: ⊦ a ' + x = a ' + y ↔ x = y; from specification list Used terms: m0, nf