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Proof step 2 from proof toinf-to-eq (previous step)

⊦ σ to∞ n∞ to∞ n∞ = σ to∞ n∞, # σ < n∞

Heuristic structural induction applied rule structural induction

And closed the goal!

Rule argument

term: n∞

Additional information

Used simplifier rules: toinf-inf: ⊦ σ to∞ ∞ = σ;%toinf-fin: ⊦ σ to∞ ⌜n⌝ = σ to n;%to-to-eq: ¬ # σ < ⌜n⌝ ⊦ σ to n to n = σ to n;%natinf freely generated by ∞, ⌜ ⌝;;