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Proof step 3 from proof toinftoinf-append-add (previous step)

n∞ = ⌜m⌝ ⊦ (σ to∞ n∞) + σ0 to∞ n∞1 + n∞ = (σ to∞ n∞) + (σ0 to∞ n∞1), # σ0 < n∞1, # σ < n∞

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ (σ to m) + σ0 to∞ n∞1 + ⌜m⌝ = (σ to m) + (σ0 to∞ n∞1), # σ0 < n∞1, # σ < ⌜m⌝

Rule argument

Additional information

Used simplifier rules: toinf-fin: ⊦ σ to∞ ⌜n⌝ = σ to n;