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Proof step 1 from proof ton-fromn-fin (conclusion)

⊦ ¬ # x < n → (x to n) from n = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n ≤ # x ⊦ (x to n) from n = []

Rule argument

Additional information

Used simplifier rules: lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat