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Proof step 12 from proof lim-exists (previous step)

# σσ[n] = ∞, # σσ = ∞, mon(σσ), n < n0 ⊦ σσ = [], n0 = 0, ∃ σ1. σσ[n0] + σ1 = σσ[n]

User applied rule exists right

And obtained the following new goals

Proof step 13:
# σσ[n] = ∞, # σσ = ∞, mon(σσ), n < n0 ⊦ σσ = [], n0 = 0, σσ[n0] + [] = σσ[n]

Rule argument

pos: right 3 terms: [] abort: F discard: T computed: F

Additional information

Used terms: []