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Proof step 126 from proof lim-exists (previous step)

# σσ = ∞, σσ[n] + ⌜nf⌝ = σσ[n + 1] ⊦ σσ = [], ∃ σ. (∀ n. ∃ σ1. σσ[n] + σ1 = σ) ∧ (∀ m. ¬ # σ < ⌜m⌝ → (∃ n, σ1. (σ to m) + σ1 = σσ[n])), ∃ n. # σσ[n] = ∞, ∃ x. σσ[n + 1] = σσ[n] + ⌜x⌝

User applied rule exists right

And obtained the following new goals

Proof step 127:
# σσ = ∞, σσ[n] + ⌜nf⌝ = σσ[n + 1] ⊦ σσ = [], ∃ σ. (∀ n. ∃ σ1. σσ[n] + σ1 = σ) ∧ (∀ m. ¬ # σ < ⌜m⌝ → (∃ n, σ1. (σ to m) + σ1 = σσ[n])), # σσ[n + 1] = ∞, ∃ x. σσ[n + 1] = σσ[n] + ⌜x⌝

Rule argument

pos: right 3 terms: n + 1 abort: F discard: T computed: F

Additional information

Used terms: n + 1