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Proof step 130 from proof lim-exists (previous step)

mon(σσ) ⊦ ∀ n. # σσ ≠ ⌜n⌝ , σσ = [], ∃ σ. (∀ n. ⌜n⌝ < # σσ → (∃ σ1. σσ[n] + σ1 = σ)) ∧ (∀ m. ¬ # σ < ⌜m⌝ → (∃ n. ⌜n⌝ < # σσ ∧ (∃ σ1. (σ to m) + σ1 = σσ[n])))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 131:
# σσ = ⌜n⌝ , mon(σσ) ⊦ σσ = [], ∃ σ. (∀ n. ⌜n⌝ < # σσ → (∃ σ1. σσ[n] + σ1 = σ)) ∧ (∀ m. ¬ # σ < ⌜m⌝ → (∃ n. ⌜n⌝ < # σσ ∧ (∃ σ1. (σ to m) + σ1 = σσ[n])))

Proof step 130 from proof lim-exists (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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