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Proof step 16 from proof lim-exists (previous step)

σσ[n] ⊑ σσ[n0], # σσ[n] = ∞, # σσ = ∞, mon(σσ), n < n0 ⊦ σσ = [], n0 = 0, σσ[n0] = σσ[n]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
# σσ[n] = ∞, # σσ = ∞, σσ[n] + σ = σσ[n0], mon(σσ), n < n0 ⊦ σσ = [], n0 = 0, σσ[n0] = σσ[n]

Rule argument

Additional information

Used simplifier rules: prefix-def: ⊦ σ ⊑ σ0 ↔ (∃ σ1. σ + σ1 = σ0);