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Proof step 18 from proof lim-unique (previous step)

# σ = # σ0, (σ to n) + σ1 = σσ[n0], ((σ0 to n) + σ2) + σ3 = σσ[n0], mon(σσ), ⌜n0⌝ < # σσ, ⌜n1⌝ < # σσ, n1 < n0, ∀ n. ⌜n⌝ < # σσ → (∃ σ1. σσ[n] + σ1 = σ), ∀ n. ⌜n⌝ < # σσ → (∃ σ1. σσ[n] + σ1 = σ0) ⊦ σσ = [], σ to n = σ0 to n, n0 = 0, # σ0 < ⌜n⌝

User applied rule insert equation

And obtained the following new goals

Proof step 19:
# σ = # σ0, ((σ0 to n) + σ2) + σ3 = (σ to n) + σ1, mon(σσ), ⌜n0⌝ < # σσ, ⌜n1⌝ < # σσ, n1 < n0, ∀ n. ⌜n⌝ < # σσ → (∃ σ1. σσ[n] + σ1 = σ), ∀ n. ⌜n⌝ < # σσ → (∃ σ1. σσ[n] + σ1 = σ0) ⊦ σσ = [], σ to n = σ0 to n, n0 = 0, # σ0 < ⌜n⌝

Rule argument

pos: left 2 flags: rotate, discard

Proof step 18 from proof lim-unique (previous step)

User applied rule insert equation

And obtained the following new goals

Rule argument

Additional information