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Proof step 58 from proof lim-unique (previous step)

∞ = # σ, (σ to n + 1) + σ1 = σσ[n0], # σσ[n0] + # σ2 = ⌜n⌝ , ⌜n0⌝ < # σσ, mon(σσ), ∀ n. ⌜n⌝ < # σσ → (∃ σ1. σσ[n] + σ1 = σ), ∀ m. ¬ n < m → (∃ n. ⌜n⌝ < # σσ ∧ (∃ σ1. (σσ[n0] + σ2 to m) + σ1 = σσ[n])) ⊦ σσ = []

User applied rule insert equation

And obtained the following new goals

Proof step 59:
∞ = # σ, (σ to n + 1) + σ1 = σσ[n0], #((σ to n + 1) + σ1) + # σ2 = ⌜n⌝ , ⌜n0⌝ < # σσ, mon(σσ), ∀ n. ⌜n⌝ < # σσ → (∃ σ1. σσ[n] + σ1 = σ), ∀ m. ¬ n < m → (∃ n. ⌜n⌝ < # σσ ∧ (∃ σ1. (σσ[n0] + σ2 to m) + σ1 = σσ[n])) ⊦ σσ = []

Rule argument

pos: left 2 flags: rotate

Proof step 58 from proof lim-unique (previous step)

User applied rule insert equation

And obtained the following new goals

Rule argument

Additional information