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Proof step 2 from proof assoc (previous step)

∀ str2, str3. (str + str2) + str3 = str + str2 + str3 ⊦ ((char + str) + str2) + str3 = (char + str) + str2 + str3

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ str2, str3. (str + str2) + str3 = str + str2 + str3 ⊦ (str + str2) + str3 = str + str2 + str3

Rule argument

Additional information

Used simplifier rules: append-rec: ⊦ (char + str) + str0 = char + (str + str0);%inj-01: ⊦ char + str1 = char + str2 ↔ str1 = str2; from specification string-data