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Proof step 1 from proof injectivity (conclusion)

⊦ char ' + str = char0 ' + str0 ↔ char = char0 ∧ str = str0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: one: ⊦ char1 ' + str1 = char2 ' + str2 ↔ char1 = char2 ∧ str1 = str2;