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Proof step 2 from proof rest (previous step)

str ≠ "" ⊦ (str + str0).rstring = str.rstring + str0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: rest-01: ⊦ str ≠ "" → (str + str0).rstring = str.rstring + str0;%app: ⊦ str + str0 = str + str1 ↔ str0 = str1;