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Proof step 1 from proof inj-03 (conclusion)

⊦ str ≠ "" ∧ str0 ≠ "" → (str = str0 ↔ str.char1 = str0.char1 ∧ str.rstring = str0.rstring)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information