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Proof step 5 from proof inj-03 (previous step)

⊦ str0 = "", str0.char1 + str0.rstring = str0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 6:
⊦ str ≠ "" → (char = str.char1 ∧ str0 = str.rstring ↔ str = char + str0)

Rule argument

spec: string-data inst: name: elim seq: ⊦ str ≠ "" → (char = str.char1 ∧ str0 = str.rstring ↔ str = char + str0) subst: [str, char0, str0] → [str0, char0, str] flags: rewrite, current

Additional information

Used terms: str0, char0, str