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Proof step 9 from proof val-total (previous step)

∀ str0, char. (∀ str2. str0 = str2 ∨ str0 < str2 ∨ str2 < str0) → char ' + str0 = str ∨ char ' + str0 < str ∨ str < char ' + str0, ∀ str2. str0 = str2 ∨ str0 < str2 ∨ str2 < str0 ⊦ char < char0, char0 < char, char = char0 ∧ str0 < str, char0 = char ∧ str < str0, char = char0 ∧ str0 = str

User applied rule insert lemma

And obtained the following new goals

Rule argument

spec: string-less inst: name: Char-total seq: ⊦ char1 < char2 ∨ char1 = char2 ∨ char2 < char1 subst: [char1, char2] → [char, char0] flags: current, []

Additional information

Used terms: char, char0