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Proof step 16 from proof val-trans (previous step)

str < str1, str0 < str, ∀ str2, str3. str0 < str2 ∧ str2 < str3 → str0 < str3, ∀ str3, char, str0. str < str3 ∧ char ' + str0 < str ∧ (∀ str2, str3. str0 < str2 ∧ str2 < str3 → str0 < str3) → char ' + str0 < str3, ∀ str0, str, char0. str0 < str ∧ char0 ' + str < str1 ∧ (∀ str3, char, str0. str < str3 ∧ char ' + str0 < str ∧ (∀ str2, str3. str0 < str2 ∧ str2 < str3 → str0 < str3) → char ' + str0 < str3) ∧ (∀ str2, str3. str0 < str2 ∧ str2 < str3 → str0 < str3) → char0 ' + str0 < str1 ⊦ str0 < str1

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: str, str1

Additional information

Used terms: str, str1