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Proof step 1 from proof append-eqlen-01 (conclusion)

⊦ # str0 = # str2 → (str + str0 = str1 + str2 ↔ str = str1 ∧ str0 = str2)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
# str0 = # str2, str + str0 = str1 + str2 ⊦ str = str1 ∧ str0 = str2

Rule argument

Additional information