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Proof step 6 from proof append-eqlen-01 (previous step)

str1 ≠ "", # str0 = # str2, (char ' + str3) + str0 = str1 + str2, ∀ str0, str2, str1. # str0 = # str2 ∧ str3 + str0 = str1 + str2 → str3 = str1 ∧ str0 = str2 ⊦ (char = str1.char1 ∧ str3 = str1.rstring) ∧ str0 = str2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
# str0 = # str2, (char ' + str3) + str0 = str1 + str2, ∀ str0, str2, str1. # str0 = # str2 ∧ str3 + str0 = str1 + str2 → str3 = str1 ∧ str0 = str2 ⊦ str1 = "", char = str1.char1 ∧ str3 = str1.rstring ∧ str0 = str2

Proof step 6 from proof append-eqlen-01 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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