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Proof step 2 from proof pos-range (previous step)

# str < pos(char, str) ⊦ pos(char, str) = 0

User applied rule structural induction

And obtained the following new goals

Proof step 3:
∀ char. # str0 < pos(char, str0) → pos(char, str0) = 0, #(char0 + str0) < pos(char, char0 + str0) ⊦ pos(char, char0 + str0) = 0

Rule argument

indvar: str

Additional information

Used simplifier rules: Pos-empty: ⊦ pos(char, "") = 0;%string freely generated by "", +;;