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Proof step 5 from proof val-total-01 (previous step)

pos(char, sortedchars) ≤ pos(char2, sortedchars) ⊦ char = char2, char < char2

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ char1 < char2 ↔ pos(char1, sortedchars) < pos(char2, sortedchars)
Proof step 7:
pos(char, sortedchars) ≤ pos(char2, sortedchars) ⊦ char = char2, pos(char, sortedchars) < pos(char2, sortedchars)

Rule argument

spec: string-less inst: name: Char-less seq: ⊦ char1 < char2 ↔ pos(char1, sortedchars) < pos(char2, sortedchars) subst: [char2, char1] → [char2, char] flags: rewrite, current

Additional information

Used terms: char2, char