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Proof step 11 from proof val-total (previous step)

∀ str0, char. (∀ str2. str0 = str2 ∨ str0 < str2 ∨ str2 < str0) → char ' + str0 = str ∨ char ' + str0 < str ∨ str < char ' + str0, ∀ str2. str0 = str2 ∨ str0 < str2 ∨ str2 < str0 ⊦ str0 = str, str0 < str, str < str0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: str

Additional information

Used terms: str