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Proof step 19 from proof eq-leninv (previous step)

⌜nσ[n]⌝ = leninv(nσ), m + 1 = nσ[n], ⌜n⌝ < # nσ, stutf(nσ) ⊦ # nσ = ∞ ∧ (∀ m. n < m ∧ ⌜m⌝ < # nσ → nσ[m] = nσ[n]), nσ[n] = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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