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Proof step 3 from proof eq-leninv (previous step)

nσ[n] = 0, ⌜n⌝ < # nσ, stutf(nσ) ⊦ ⌜nσ[n]⌝ = leninv(nσ) ↔ # nσ = ∞ ∧ (∀ m. n < m ∧ ⌜m⌝ < # nσ → nσ[m] = nσ[n])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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