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Proof step 31 from proof eq-leninv (previous step)

nσ[m2] + 1 = nσ[n], # nσ = ∞, n < m0, stutf(nσ), ∀ m1. m2 < m1 → nσ[m1] = nσ[n] ⊦ m0 = 0, nσ[m0] = nσ[n]

User applied rule insert lemma

And obtained the following new goals

Proof step 32:
⊦ mon≤(nσ) ∧ m ≤ n ∧ ⌜n⌝ < # nσ → nσ[m] ≤ nσ[n]
Proof step 33:
mon≤(nσ) ∧ n ≤ m0 ∧ ⌜m0⌝ < # nσ → nσ[n] ≤ nσ[m0], nσ[m2] + 1 = nσ[n], # nσ = ∞, n < m0, stutf(nσ), ∀ m1. m2 < m1 → nσ[m1] = nσ[n] ⊦ m0 = 0, nσ[m0] = nσ[n]

Rule argument

spec: inst: name: monle-leq seq: ⊦ mon≤(nσ) ∧ m ≤ n ∧ ⌜n⌝ < # nσ → nσ[m] ≤ nσ[n] subst: [nσ, m, n] → [nσ, n, m0] flags: current, []

Additional information

Used terms: nσ, n, m0