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Proof step 45 from proof eq-leninv (previous step)

# nσ = ∞ ∧ (∀ m. n < m ∧ ⌜m⌝ < # nσ → nσ[m] = nσ[n]), m + 1 = nσ[n], ⌜n⌝ < # nσ, stutf(nσ) ⊦ ⌜nσ[n]⌝ = leninv(nσ), nσ[n] = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 46:
m + 1 = nσ[n], # nσ = ∞, stutf(nσ), ∀ m0. n < m0 → nσ[m0] = nσ[n] ⊦ nσ[n] = 0, ⌜nσ[n]⌝ = leninv(nσ)

Rule argument

Additional information

Used simplifier rules: less-inf2: ⊦ ⌜m⌝ < ∞; from specification nat-inf