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Proof step 52 from proof eq-leninv (previous step)

stutf(nσ), m + 1 = nσ[n], # nσ = ∞, stutf(nσ), ∀ m0. n < m0 → nσ[m0] = nσ[n] ⊦ (# nσ = ∞ ⊃ ∃ m0. nσ[m0] = m ∧ (∀ m1. m0 < m1 → nσ[m1] = m + 1);nσ[(# nσ).n - 1] = m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 53:
m + 1 = nσ[n], # nσ = ∞, stutf(nσ), ∀ m0. n < m0 → nσ[m0] = nσ[n] ⊦ ∃ m0. nσ[m0] = m ∧ (∀ m1. m0 < m1 → nσ[m1] = nσ[m0] + 1)

Proof step 52 from proof eq-leninv (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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