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Proof step 7 from proof eq-leninv (previous step)

# nσ = ∞ ∧ (∀ m. n < m ∧ ⌜m⌝ < # nσ → nσ[m] = 0), stutf(nσ), nσ[n] = 0, ⌜n⌝ < # nσ, stutf(nσ) ⊦ nσ = ⌜λ n. 0⌝

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
nσ[n] = 0, # nσ = ∞, stutf(nσ), ∀ m. n < m → nσ[m] = 0 ⊦ nσ = ⌜λ n. 0⌝

Rule argument

Additional information

Used simplifier rules: less-inf2: ⊦ ⌜m⌝ < ∞; from specification nat-inf