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Proof step 161 from proof inv-get-inverse-between (previous step)

∀ n0. m0 < n0 ∨ nσ[n0] ≠ nσ[m1], # nσ = ⌜m0⌝ + ⌜1⌝ , m1 ≤ m0, ∞.n + m + 1 < max∞(λ n0. ¬ m0 < n0 ∧ nσ[n0] = nσ[m1] + 1).n, nσ[m1] < nσ[m0], stutf(nσ) ⊦ max∞(λ n0. ¬ m0 < n0 ∧ nσ[n0] = nσ[m1] + 1).n = 0, nσ[∞.n + m + 1] = nσ[m1] + 1, nσ[m0] = 0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: m1

Additional information

Used simplifier rules: le-ls-simp: ⊦ m ≤ n → (n < m ↔ false); from specification nat Used terms: m1