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Proof step 171 from proof inv-get-inverse-between (previous step)

(∀ n. ∃ n0. n < n0 ∧ ¬ m0 < n0 ∧ nσ[n0] = nσ[n1] + 1) ∨ (∀ n. ¬(¬ m0 < n ∧ nσ[n] = nσ[n1] + 1)), # nσ = ⌜m0⌝ + ⌜1⌝ , n1 + m + 1 < ∞.n, nσ[n1] < nσ[m0], stutf(nσ), n1 ≤ m0, ∀ m. ¬ m0 < m ∧ nσ[m] = nσ[n1] → ¬ n1 < m ⊦ ∞.n = 0, nσ[n1 + m + 1] = nσ[n1] + 1, nσ[m0] = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 172:
# nσ = ⌜m0⌝ + ⌜1⌝ , n1 + m + 1 < ∞.n, nσ[n1] < nσ[m0], stutf(nσ), n1 ≤ m0, ∀ m. ¬ m0 < m ∧ nσ[m] = nσ[n1] → ¬ n1 < m, (∀ n. ∃ n0. n < n0 ∧ ¬ m0 < n0 ∧ nσ[n0] = nσ[n1] + 1) ∨ (∀ n. m0 < n ∨ nσ[n] ≠ nσ[n1] + 1) ⊦ ∞.n = 0, nσ[n1 + m + 1] = nσ[n1] + 1, nσ[m0] = 0

Proof step 171 from proof inv-get-inverse-between (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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