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Proof step 177 from proof inv-get-inverse-between (previous step)

∀ n. m0 < n ∨ nσ[n] ≠ nσ[m1], # nσ = ⌜m0⌝ + ⌜1⌝ , nσ[m1] = nσ[n1] + 1, n1 + m + 1 < ∞.n, nσ[n1] < nσ[m0], stutf(nσ), n1 ≤ m0, m1 ≤ m0, nσ[m1] ≤ nσ[m0], ∀ m. ¬ m0 < m ∧ nσ[m] = nσ[n1] → ¬ n1 < m ⊦ ∞.n = 0, nσ[n1 + m + 1] = nσ[m1], nσ[m0] = 0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: m1

Additional information

Used simplifier rules: le-ls-simp: ⊦ m ≤ n → (n < m ↔ false); from specification nat Used terms: m1