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Proof step 66 from proof inv-get-inverse-between (previous step)

# nσ = ∞, ⌜n⌝ + ⌜1⌝ < leninv(nσ), stutf(nσ), max∞(λ n0. nσ[n0] = n).n + m + 1 < max∞(λ n0. nσ[n0] = n + 1).n, ∀ m. ∃ m0. m < nσ[m0], ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦ ∀ n. ∃ m. nσ[m] = n, max∞(λ n0. nσ[n0] = n + 1).n = 0, nσ[max∞(λ n0. nσ[n0] = n).n + m + 1] = n + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 67:
# nσ = ∞, ⌜n⌝ + ⌜1⌝ < leninv(nσ), stutf(nσ), max∞(λ n0. nσ[n0] = n).n + m + 1 < max∞(λ n0. nσ[n0] = n + 1).n, ∀ m. ∃ m0. m < nσ[m0], ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦ max∞(λ n0. nσ[n0] = n + 1).n = 0, nσ[max∞(λ n0. nσ[n0] = n).n + m + 1] = n + 1, ∃ m. nσ[m] = n0

Proof step 66 from proof inv-get-inverse-between (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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