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Proof step 78 from proof inv-get-inverse-between (previous step)

# nσ = ∞, nσ[m1] = nσ[m] + 1, nσ[m] < nσ[m0], m < m0, stutf(nσ), m1 ≤ m0, nσ[m1] ≤ nσ[m0] ⊦ nσ[m0] = 0, m0 = 0, ∃ m0. nσ[m0] = nσ[m1]

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 3 terms: m1

Additional information

Used terms: m1