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Proof step 1 from proof inv-get-inverse-last (conclusion)
⊦ stutf(nσ) ∧ ⌜n⌝ + ⌜1⌝ = leninv(nσ) ∧ ⌜inv(nσ)[n]⌝ + ⌜m⌝ + ⌜1⌝ < # nσ → nσ[inv(nσ)[n] + m + 1] = n + 1
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
⌜n⌝ + ⌜1⌝ = leninv(nσ), stutf(nσ), ⌜inv(nσ)[n]⌝ + ⌜m⌝ + ⌜1⌝ < # nσ ⊦ nσ[inv(nσ)[n] + m + 1] = n + 1
Rule argument
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