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Proof step 10 from proof inv-get-inverse-last (previous step)

leninv(nσ) = ⌜1⌝ + ⌜n⌝ , ⌜max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n⌝ + ⌜m⌝ + ⌜1⌝ < # nσ, stutf(nσ) ⊦ nσ[max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n + m + 1] = n + 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ n∞1 + n∞2 = n∞2 + n∞1
Proof step 12:
leninv(nσ) = ⌜n⌝ + ⌜1⌝ , ⌜max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n⌝ + ⌜m⌝ + ⌜1⌝ < # nσ, stutf(nσ) ⊦ nσ[max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n + m + 1] = n + 1

Rule argument

spec: nat-inf inst: name: add-comm seq: ⊦ n∞1 + n∞2 = n∞2 + n∞1 subst: [n∞2, n∞1] → [⌜n⌝ , ⌜1⌝ ] flags: rewrite

Additional information

Used terms: ⌜n⌝ , ⌜1⌝