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Proof step 35 from proof inv-get-inverse-last (previous step)

# nσ ≠ ∞, nσ[(# nσ).n - 1] = n, ∀ n0. ⌜n0⌝ < # nσ → nσ[n0] < n, max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n) = ∞, ⌜∞.n⌝ + ⌜m⌝ + ⌜1⌝ < # nσ, stutf(nσ) ⊦ nσ[∞.n + m + 1] = n + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 36:
max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = nσ[(# nσ).n - 1]) = ∞, ⌜∞.n⌝ + ⌜m⌝ + ⌜1⌝ < # nσ, stutf(nσ), ∀ n0. ⌜n0⌝ < # nσ → nσ[n0] < nσ[(# nσ).n - 1] ⊦ nσ[∞.n + m + 1] = nσ[(# nσ).n - 1] + 1, # nσ = ∞

Proof step 35 from proof inv-get-inverse-last (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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