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Proof step 46 from proof inv-get-inverse-last (previous step)

(⌜n1⌝ < # nσ ∧ nσ[n1] = n) ∧ (∀ m. ⌜m⌝ < # nσ ∧ nσ[m] = n → ¬ n1 < m), ⌜n1⌝ + ⌜m⌝ + ⌜1⌝ < # nσ, stutf(nσ), (# nσ = ∞ ⊃ nσ[m1] = n ∧ (∀ m0. m1 < m0 → nσ[m0] = nσ[m1] + 1);nσ[(# nσ).n - 1] = n) ⊦ nσ[n1 + m + 1] = n + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 47:
⌜n1⌝ < # nσ, ⌜n1⌝ + ⌜m⌝ + ⌜1⌝ < # nσ, stutf(nσ), ∀ m. ⌜m⌝ < # nσ ∧ nσ[m] = nσ[n1] → ¬ n1 < m, (# nσ = ∞ ⊃ nσ[m1] = nσ[n1] ∧ (∀ m0. m1 < m0 → nσ[m0] = nσ[m1] + 1);nσ[(# nσ).n - 1] = nσ[n1]) ⊦ nσ[n1 + m + 1] = nσ[n1] + 1

Proof step 46 from proof inv-get-inverse-last (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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