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Proof step 53 from proof inv-get-inverse-last (previous step)

mon≤(nσ) ∧ n1 ≤ m1 ∧ ⌜m1⌝ < # nσ → nσ[n1] ≤ nσ[m1], nσ[m1] = nσ[n1], # nσ = ∞, stutf(nσ), n1 ≤ m1, ∀ m0. m1 < m0 → nσ[m0] = nσ[n1] + 1, ∀ m0. nσ[m0] = nσ[n1] → ¬ n1 < m0 ⊦ nσ[n1 + m + 1] = nσ[n1] + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 54:
# nσ = ∞, nσ[m1] = nσ[n1], n1 ≤ m1, stutf(nσ), ∀ m0. nσ[m0] = nσ[n1] → ¬ n1 < m0, ∀ m0. m1 < m0 → nσ[m0] = nσ[n1] + 1 ⊦ nσ[n1 + m + 1] = nσ[n1] + 1

Rule argument

Additional information

Used simplifier rules: stutf-monle: ⊦ stutf(nσ) → (¬ mon≤(nσ) ↔ false);%ler: ⊦ m ≤ m; from specification nat