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Proof step 59 from proof inv-get-inverse-last (previous step)

# nσ ≠ ∞, nσ[(# nσ).n - 1] = nσ[n1], ⌜n1⌝ < # nσ, ⌜n1⌝ + ⌜m⌝ + ⌜1⌝ < # nσ, stutf(nσ), ∀ m. ⌜m⌝ < # nσ ∧ nσ[m] = nσ[n1] → ¬ n1 < m ⊦ nσ[n1 + m + 1] = nσ[n1] + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 60:
nσ[(# nσ).n - 1] = nσ[n1], ⌜n1⌝ < # nσ, ⌜n1⌝ + ⌜m⌝ + ⌜1⌝ < # nσ, stutf(nσ), ∀ m. ⌜m⌝ < # nσ ∧ nσ[m] = nσ[n1] → ¬ n1 < m ⊦ nσ[n1 + m + 1] = nσ[n1] + 1, # nσ = ∞

Proof step 59 from proof inv-get-inverse-last (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information