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Proof step 64 from proof inv-get-inverse-last (previous step)

# nσ = ⌜m1⌝ + ⌜1⌝ , nσ[m1] = nσ[n1], n1 ≤ m1, m + n1 < m1, stutf(nσ), ∀ m0. ¬ m1 < m0 ∧ nσ[m0] = nσ[n1] → ¬ n1 < m0 ⊦ nσ[n1 + m + 1] = nσ[n1] + 1

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: m1

Additional information

Used simplifier rules: ref-1: ⊦ ¬ n < n; from specification nat-basic1%nls-fst: ⊦ ¬ m < n → ¬ m + m0 < n; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2 Used terms: m1