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Proof step 1 from proof inv-get-inverse-succ-inf (conclusion)
⊦ stutf(nσ) ∧ ⌜n⌝ < leninv(nσ) ∧ # nσ = ∞ → nσ[inv(nσ)[n] + 1] = n + 1
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
# nσ = ∞, stutf(nσ), ⌜n⌝ < leninv(nσ) ⊦ nσ[inv(nσ)[n] + 1] = n + 1
Rule argument
Additional information