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Proof step 107 from proof inv-get-inverse-succ (previous step)

max∞(λ n0. ¬ m < n0 ∧ nσ[n0] = n) = ⌜n1⌝ , # nσ = ⌜m⌝ + ⌜1⌝ , stutf(nσ), n ≤ nσ[m], n1 < m ⊦ max∞(λ n0. ¬ m < n0 ∧ nσ[n0] = n) = ∞, nσ[n1 + 1] = n + 1, m = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 108:
# nσ = ⌜m⌝ + ⌜1⌝ , max∞(λ n0. ¬ m < n0 ∧ nσ[n0] = n) = ⌜n1⌝ , n1 < m, n ≤ nσ[m], stutf(nσ) ⊦ m = 0, nσ[n1 + 1] = n + 1

Rule argument

Additional information

Used simplifier rules: disj: ⊦ ⌜m⌝ ≠ ∞; from specification nat-inf-basic