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Proof step 116 from proof inv-get-inverse-succ (previous step)

# nσ = ⌜m⌝ + ⌜1⌝ , nσ[0] = 0, n1 < m, nσ[n1] ≤ nσ[m], ∀ m0. ¬ m < m0 ∧ nσ[m0] = nσ[n1] → ¬ n1 < m0, ∀ n. n < m → nσ[n + 1] = nσ[n] ∨ nσ[n + 1] = nσ[n] + 1 ⊦ m = 0, nσ[n1 + 1] = nσ[n1] + 1, nσ[n1 + 1] = nσ[n1], nσ = []

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: n1

Additional information

Used terms: n1