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Proof step 48 from proof inv-get-inverse-succ (previous step)

# nσ = ∞, nσ[n1] = n ∧ (∀ m. nσ[m] = n → ¬ n1 < m), stutf(nσ), ⌜n⌝ < leninv(nσ), ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0], ∀ m. ∃ m0. m < nσ[m0] ⊦ nσ[n1 + 1] = n + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 49:
# nσ = ∞, stutf(nσ), ⌜nσ[n1]⌝ < leninv(nσ), ∀ m. nσ[m] = nσ[n1] → ¬ n1 < m, ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0], ∀ m. ∃ m0. m < nσ[m0] ⊦ nσ[n1 + 1] = nσ[n1] + 1

Proof step 48 from proof inv-get-inverse-succ (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information